Name your submission Lastname_GeneticsProblems and submit it in the ‘Assignments’ link under the ‘Assessments’ tab on the course homepage. Each question is worth 10 points. The maximum score for this assignment is 100 points.1. In garden peas, yellow (Y) seed color is dominant to green (y). Because yellow and green are two different forms of the same gene (seed color), they are alleles. Use a Punnett square to show a cross between two heterozygous pea plants.  What is the phenotype(s) of the offspring? What is the genotype(s) of the offspring?Show the cross: __________ X ____________ (what is the genetic makeup of each parent based on the information given in this question).

Complete the Punnett square for that cross. (The potential alleles which can be provided from one parent go into the top row and the alleles of the other parent go into the left column; the remaining 4 larger boxes are for the pairs of alleles the offspring would receive as a result of this potential mating.)

Genotypes:Phenotypes:2. Assume that white color (W) is dominant over yellow color (w) in corn.  Perform a Punnett square for a cross where pollen from the anthers of a plant that is heterozygous for color is placed on the pistil of a yellow-fruited plant.  What are the genotypes and phenotypes you would expect to find from this cross? Complete the Punnett square for that cross. (The potential alleles which can be provided from one parent go into the top row and the alleles of the other parent go into the left column; the remaining 4 larger boxes are for the pairs of alleles the offspring would receive as a result of this potential mating.)Genotypes;Phenotypes:Use the information below to answer questions 3-6.There may be a number of possible alleles for a given gene within a population. In a multiple allele system, the dominance relationships between the various alleles must be considered. One of the more familiar examples of a multiple allelic system is that of human ABO blood types. The gene involved codes for a protein on the outside of red bloods cells. Three alleles (IA, IB and i) determine whether the protein is present or absent and the form of the protein present.  The A and B alleles code for the A and B forms of the protein and are co-dominant to each other. The O allele (i) codes for no protein and is recessive to both A and B alleles. This means there are four possible blood types (A, AB, B, and O). 3. Show the possible genotypes and phenotypes of the offspring from a cross between a homozygous male with type A blood and a homozygous female with type B blood. Complete the Punnett square for that cross. (The potential alleles which can be provided from one parent go into the top row and the alleles of the other parent go into the left column; the remaining 4 larger boxes are for the pairs of alleles the offspring would receive as a result of this potential mating.)Genotypes:Phenotypes:4. Show the possible genotypes and phenotypes of the offspring from a cross between a heterozygous male with type A blood and a heterozygous female with type B blood.Complete the Punnett square for that cross. (The potential alleles which can be provided from one parent go into the top row and the alleles of the other parent go into the left column; the remaining 4 larger boxes are for the pairs of alleles the offspring would receive as a result of this potential mating.)Genotypes:Phenotypes:5. If a man with blood type A, one of whose parents had blood type O, marries a woman with blood type AB, what are the putative genotypes of the offspring?Complete the Punnett square for that cross. (The potential alleles which can be provided from one parent go into the top row and the alleles of the other parent go into the left column; the remaining 4 larger boxes are for the pairs of alleles the offspring would receive as a result of this potential mating.)Genotypes:6.  A couple with the following blood types: the man has type AB and the woman has type B, discover their child has type O blood.    Is it possible that one of these ‘parents’ may not actually be the genetic parent of this child?  If so, which one, and how do you know?__________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________7. In horses coat color shows incomplete dominance: the alleles are chestnut color (Hc) and cremello (Hcr); heterozygous individuals have the phenotype palamino. What are the predicted phenotypes from a cross between a palamino and cremello colored horses? What are the genotypes?Complete the Punnett square for that cross. (The potential alleles which can be provided from one parent go into the top row and the alleles of the other parent go into the left column; the remaining 4 larger boxes are for the pairs of alleles the offspring would receive as a result of this potential mating.)Genotypes:Phenotypes:8.   Red-green color blindness is inherited as an X-linked recessive (Xc).  If a color-blind man marries a woman who is heterozygous for normal vision, what would be the expected phenotypes of their children with reference to this character?  In your answer, specify in your phenotype descriptions the gender of the children.  (For example, don’t just say 75% of the children would be colorblind – you would instead say 100 % of the daughters would be colorblind and 50% of the sons would be colorblind.  Note that this is not a correct answer; it is just to give you an idea of how to explain the correct phenotypes of the cross.)Complete the Punnett square for that cross. (The potential alleles which can be provided from one parent go into the top row and the alleles of the other parent go into the left column; the remaining 4 larger boxes are for the pairs of alleles the offspring would receive as a result of this potential mating.)Phenotypes by gender: 9.   Hemophilia is another example of a X-linked disease caused when a recessive allele (Xh) is expressed. If a normal male reproduces with a heterozygous normal female, what are the expected genotypes and phenotypes? Will any of their daughters develop hemophilia?  As in the previous question, you must also give the gender of the child in your genotype and phenotype descriptions here.Complete the Punnett square for that cross. (The potential alleles which can be provided from one parent go into the top row and the alleles of the other parent go into the left column; the remaining 4 larger boxes are for the pairs of alleles the offspring would receive as a result of this potential mating.)Genotypes by gender:Phenotypes by gender: 10. The question below involves what’s called a dihybrid cross (all your previous questions involved monohybrid crosses).  A dihybrid cross is where you follow alleles for 2 different traits together – in the example below one trait is represented by the letter R (or r) and the other by the letter Y (or y). So, you need to show adults and offspring with 4 letters (RRYy, for example) to indicate a proper genotype; and the alleles passed on from each parent would be pairs of alleles (for the RRYy individual in the example above, they could possibly pass on the combinations of RY, or Ry to an individual offspring).Question: In pea plants, seed shape and seed color are controlled by genes located on different chromosomes. Seeds may be round (R) or wrinkled (r), with the allele for round seeds being dominant. Alleles for seed color are yellow and green, with the green allele (y) recessive to the yellow (Y) allele. If you cross an individual that is homozygous round and yellow with an individual that is homozygous for wrinkled and green, what is the genotype of the offspring resulting from this mating? Provide both the cross and the resulting Punnett square.Show the cross: __________ X ____________ (what is the genetic makeup of each parent based on the information given in this question – 4 letters for each in this one).

Draw your own Punnett square (remember you will be combining pairs of letters from the parents to end up with offspring each with 4 letters representing the inherited alleles).  For these types of dihybrid crosses you could end up with anywhere from 1 to 16 boxes for offspring depending on what you are crossing.  It’s not necessarily going to be 4 boxes for offspring this time.The genotype of the offspring: